Download CCNP Implementing Cisco IP Routing (ROUTE v2-0).test4prep.300-101.2019-01-28.1e.458q.vcex

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Exam Implementing Cisco IP Routing (ROUTE v2.0)
Number 300-101
File Name CCNP Implementing Cisco IP Routing (ROUTE v2-0).test4prep.300-101.2019-01-28.1e.458q.vcex
Size 20.57 Mb
Posted January 28, 2019
Downloads 229
Download CCNP Implementing Cisco IP Routing (ROUTE v2-0).test4prep.300-101.2019-01-28.1e.458q.vcex

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Demo Questions

Question 1

Which three problems result from application mixing of UDP and TCP streams within a network with no QoS? (Choose three.)

  • A: starvation
  • B: jitter
  • C: latency
  • D: windowing
  • E: lower throughput

Correct Answer: ACE

It is a general best practice not to mix TCP-based traffic with UDP-based traffic (especially streaming video) within a single service provider class due to the behaviors of these protocols during periods of congestion. Specifically, TCP transmitters will throttle-back flows when drops have been detected. Although some UDP applications have application-level windowing, flow control, and retransmission capabilities, most UDP transmitters are completely oblivious to drops and thus never lower transmission rates due to dropping. When TCP flows are combined with UDP flows in a single service provider class and the class experiences congestion, then TCP flows will continually lower their rates, potentially giving up their bandwidth to drop-oblivious UDP flows. This effect is called TCP-starvation/UDP-dominance. This can increase latency and lower the overall throughput. 
TCP-starvation/UDP-dominance likely occurs if (TCP-based) mission-critical data is assigned to the same service provider class as (UDP-based) streaming video and the class experiences sustained congestion. Even if WRED is enabled on the service provider class, the same behavior would be observed, as WRED (for the most part) only affects TCP-based flows.  
Granted, it is not always possible to separate TCP-based flows from UDP-based flows, but it is beneficial to be aware of this behavior when making such application-mixing decisions. 

Question 2

Which method allows IPv4 and IPv6 to work together without requiring both to be used for a single connection during the migration process?

  • A: dual-stack method
  • B: 6to4 tunneling
  • C: GRE tunneling
  • D: NAT-PT

Correct Answer: A

Dual stack means that devices are able to run IPv4 and IPv6 in parallel. It allows hosts to simultaneously reach IPv4 and IPv6 content, so it offers a very flexible coexistence strategy. For sessions that support IPv6, IPv6 is used on a dual stack endpoint. If both endpoints support Ipv4 only, then IPv4 is used. 
Native dual stack does not require any tunneling mechanisms on internal networks 
Both IPv4 and IPv6 run independent of each other 
Dual stack supports gradual migration of endpoints, networks, and applications. 

Question 3

Which statement about the use of tunneling to migrate to IPv6 is true?

  • A: Tunneling is less secure than dual stack or translation.
  • B: Tunneling is more difficult to configure than dual stack or translation.
  • C: Tunneling does not enable users of the new protocol to communicate with users of the old protocol without dual-stack hosts.
  • D: Tunneling destinations are manually determined by the IPv4 address in the low-order 32 bits of IPv4-compatible IPv6 addresses.

Correct Answer: C

Using the tunneling option, organizations build an overlay network that tunnels one protocol over the other by encapsulating IPv6 packets within IPv4 packets and IPv4 packets within IPv6 packets. The advantage of this approach is that the new protocol can work without disturbing the old protocol, thus providing connectivity between users of the new protocol.  
Tunneling has two disadvantages, as discussed in RFC 6144: 
Users of the new architecture cannot use the services of the underlying infrastructure.  
Tunneling does not enable users of the new protocol to communicate with users of the old protocol without dual-stack hosts, which negates interoperability. 

Question 4

A network administrator executes the command clear ip route. Which two tables does this command clear and rebuild? (Choose two.)

  • A: IP routing
  • B: FIB
  • C: ARP cache
  • D: MAC address table
  • E: Cisco Express Forwarding table
  • F: topology table

Correct Answer: AB

To clear one or more entries in the IP routing table, use the following commands in any mode:



Question 5

Which switching method is used when entries are present in the output of the command show ip cache?

  • A: fast switching
  • B: process switching
  • C: Cisco Express Forwarding switching
  • D: cut-through packet switching

Correct Answer: A

Fast switching allows higher throughput by switching a packet using a cache created by the initial packet sent to a particular destination. Destination addresses are stored in the high-speed cache to expedite forwarding. Routers offer better packet-transfer performance when fast switching is enabled. Fast switching is enabled by default on all interfaces that support fast switching. 
To display the routing table cache used to fast switch IP traffic, use the “show ip cache” EXEC command. 

Question 6

Which two actions must you perform to enable and use window scaling on a router? (Choose two.)

  • A: Execute the command ip tcp window-size 65536.
  • B: Set window scaling to be used on the remote host.
  • C: Execute the command ip tcp queuemax.
  • D: Set TCP options to "enabled" on the remote host.
  • E: Execute the command ip tcp adjust-mss.

Correct Answer: AB

The TCP Window Scaling feature adds support for the Window Scaling option in RFC 1323, TCP Extensions for High Performance. A larger window size is recommended to improve TCP performance in network paths with large bandwidth-delay product characteristics that are called Long Fat Networks (LFNs). The TCP Window Scaling enhancement provides that support.  
The window scaling extension in Cisco IOS software expands the definition of the TCP window to 32 bits and then uses a scale factor to carry this 32-bit value in the 16-bit window field of the TCP header. The window size can increase to a scale factor of 14. Typical applications use a scale factor of 3 when deployed in LFNs. 
The TCP Window Scaling feature complies with RFC 1323. The larger scalable window size will allow TCP to perform better over LFNs. Use the ip tcp window-size command in global configuration mode to configure the TCP window size. In order for this to work, the remote host must also support this feature and its window size must be increased.

Question 7

Refer to the exhibit. 


Which command only announces the network out of FastEthernet 0/0?

  • A: distribute list 1 out
  • B: distribute list 1 out FastEthernet0/0
  • C: distribute list 2 out
  • D: distribute list 2 out FastEthernet0/0

Correct Answer: D

Access list 2 is more specific, allowing only, whereas access list 1 permits all networks. This question also asks us to apply this distribute list only to the outbound direction of the fast Ethernet 0/0 interface, so the correct command is “distribute list 2 out FastEthernet0/0.”

Question 8

Which prefix is matched by the command ip prefix-list name permit ge 24 le 24?

  • A:
  • B:
  • C:
  • D:

Correct Answer: B

With prefix lists, the ge 24 term means greater than or equal to a /24 and the le 24 means less than or equal to /24, so only a /24 is both greater than or equal to 24 and less than or equal to 24. This translates to any prefix in the 10.8.x.0/24 network, where X is any value in the 0-255 range. Only the choice of matches this.

Question 9

Router A and Router B are configured with IPv6 addressing and basic routing capabilities using oSPFv3. The networks that are advertised from Router A do not show up in Router B's routing table. After debugging IPv6 packets, the message "not a router" is found in the output. Why is the routing information not being learned by Router B?

  • A: OSPFv3 timers were adjusted for fast convergence.
  • B: The networks were not advertised properly under the OSPFv3 process.
  • C: An IPv6 traffic filter is blocking the networks from being learned via the Router B interface that is connected to Router A.
  • D: IPv6 unicast routing is not enabled on Router A or Router B.

Correct Answer: D



Question 10

After you review the output of the command show ipv6 interface brief, you see that several IPv6 addresses have the 16-bit hexadecimal value of "fFFE" inserted into the address. Based on this information, what do you conclude about these IPv6 addresses?

  • A: IEEE EUI-64 was implemented when assigning IPv6 addresses on the device.
  • B: The addresses were misconfigured and will not function as intended.
  • C: IPv6 addresses containing "FFFE" indicate that the address is reserved for multicast.
  • D: The IPv6 universal/local flag (bit 7) was flipped.
  • E: IPv6 unicast forwarding was enabled, but IPv6 Cisco Express Forwarding was disabled.

Correct Answer: A

Extended Unique Identifier (EUI), as per RFC2373, allows a host to assign iteslf a unique 64-Bit IP Version 6 interface identify them EUI-64). This feature is a key benefit over IPv4 as it eliminates the need of manual configuration or DHCP as in the world of IPv4. The IPv6 EUI-64 format address is obtained through the 48-bit MAC address. The Mac address is first separated into two 24-bits, with one being OUI (Organizationally Unique Identifier) and the other being NIC specific. The 16-bit 0xFFFE is then inserted between these two 24-bits to for the 64-bit EUI address. IEEE has chosen FFFE as a reserved value which can only appear in EUI-64 generated from the EUI-48 MAC address. 
Here is an example showing how the Mac Address is used to generate EUI. 


Next, the seventh bit from the left, or the universal/local (U/L) bit, needs to be inverted. This bit identifies whether this interface identifier is universally or locally administered. If 0, the address is locally administered and if 1, the address is globally unique. It is worth noticing that in the OUI portion, the globally unique addresses assigned by the IEEE have always been set to 0 whereas the locally created addresses have 1 configured. Therefore, when the bit is inverted, it maintains its original scope (global unique address is still global unique and vice versa). The reason for inverting can be found in RFC4291 section 2.5.1. 


Once the above is done, we have a fully functional EUI-64 format address. 





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